We want to solve for the Maximum A Posterior solution:
$$\arg \max - \frac{1}{2} \parallel {\color{Orchid} y} - {\color{SkyBlue} x} \parallel_2^2 + \log p_\theta({\color{SkyBlue} x})$$ This can be done by gradient descent as long as one has access to $\frac{\color{orange} d \color{orange}\log \color{orange}p\color{orange}(\color{orange}x\color{orange})}{\color{orange} d \color{orange}x}$.$\Longrightarrow$ We can see which parts of the image are well constrained by data, and which regions are uncertain.
Thank you!